jar A contains 6 red balls and 4 white balls. Jar B contains 7 red balls and 2 white balls. You randomly select one ball from Jar A and, without knowing it’s color, drop it into Jar B. You then randomly select one ball from Jar B. What is the probability that the ball you select from Jar B will be red?
* is it 6/10 or 1/10?
6/10 * 8/10
To find the probability that the ball you select from Jar B will be red, you need to consider the possible outcomes and their likelihoods.
Let's break it down step by step:
Step 1: Selection from Jar A
You have two possibilities when selecting a ball from Jar A: either a red ball or a white ball. Since there are 6 red balls and 4 white balls in Jar A, the probability of selecting a red ball from Jar A is 6/10, or simplifying further, 3/5.
Step 2: Placing the ball in Jar B
After selecting a ball from Jar A, you drop it into Jar B without knowing its color. However, this doesn't change the total number of balls or their colors. So, the number of red balls in Jar B remains 7, and the number of white balls remains 2.
Step 3: Selection from Jar B
Now that you have one additional ball in Jar B, there are a total of 9 balls in it. Out of these 9 balls, 7 are red and 2 are white (since we didn't change the number of balls from the original Jar B). Therefore, the probability of selecting a red ball from Jar B is 7/9.
In conclusion, the probability that the ball you select from Jar B will be red is 7/9.