if a die is tossed four times what is the probability of getting at least one six
To calculate the probability of getting at least one six when a die is tossed four times, we can use the concept of complement probability.
First, let's find the probability of not getting a six in a single toss. The die has 6 sides, so the probability of not getting a six is 5/6 (since there are five other outcomes).
Now, since the tosses are independent events, we can multiply the probabilities for each toss. So, the probability of not getting a six in all four tosses is (5/6)^4.
To find the probability of getting at least one six, we subtract the probability of not getting a six from 1. So, the probability of getting at least one six in four tosses is 1 - (5/6)^4.
Let's calculate it:
Probability of not getting a six in a single toss = 5/6
Probability of not getting a six in four tosses = (5/6)^4 ≈ 0.4823
Now, subtracting this from 1 will give us:
Probability of getting at least one six in four tosses = 1 - 0.4823 ≈ 0.5177
Therefore, the probability of getting at least one six when a die is tossed four times is approximately 0.5177, or 51.77%.