Looking down from a stationary tree branch, a merry-go-round spins in a counterclockwise direction with an angular velocity of 1 radian per second. a squirrel of mass 0.2 kg sits on the outer rim of the merry-go-round, at a radius of 2.0 meters.

a) What is the magnitude and direction of the vector omega?

To find the magnitude and direction of the vector omega (angular velocity), we can use the given information that the merry-go-round is spinning counterclockwise with an angular velocity of 1 radian per second.

The magnitude of the angular velocity can be calculated as the absolute value of the given value, which in this case is 1 radian per second.

The direction of the angular velocity vector can be determined by using the right-hand rule. If you curl your fingers in the direction of the rotation (counterclockwise), your thumb points in the direction of the angular velocity vector. So in this case, the direction of the angular velocity vector is upward.

Therefore, the magnitude of the vector omega is 1 rad/s and its direction is upward.

The magnitude of the angular velocity vector, ω (omega), is given as 1 radian per second.

Since the merry-go-round is spinning counterclockwise, the direction of the angular velocity vector is also counterclockwise.

vector omega?

omega is angular velocity in my book.