ted skated through one of the face off circles at a hockey rink. His path through the circle is shown in the figure. Given that the face off circle is 15 feet in diameter what distance within the face off circle did Ted travel??
If you google this there will be documents so the pic can show up but IDK how to solve can anyone help
Easy. YOu know you have two intersection chords. http://www.mathopenref.com/chordsintersecting.html
the unmarked part of the diameter is 15-4=11
let x be the unmarked part of the path.
so...
4*11=5x
x=44/5
path then is 44/5 + 5
Thank you
To determine the distance within the face-off circle that Ted traveled, we need to use the formula for the circumference of a circle.
The formula to calculate the circumference of a circle is given by C = πd, where C is the circumference and d is the diameter.
In this case, the diameter of the face-off circle is given as 15 feet. Hence, we can calculate the circumference as follows:
C = π * d
C = π * 15
C ≈ 3.14 * 15
C ≈ 47.1 feet
Therefore, the distance within the face-off circle that Ted traveled is approximately 47.1 feet.
To find the distance within the face-off circle that Ted traveled, we can use the concept of circumference, which is the distance around a circle. The formula for the circumference of a circle is given by:
C = πd
where C is the circumference and d is the diameter of the circle. In this case, the diameter of the face-off circle is 15 feet.
Substituting the given value into the formula:
C = π * 15
To find the distance within the face-off circle that Ted traveled, we need to determine what fraction of the circumference he covered. Since we have a figure showing Ted's path through the circle, we can estimate this visually. Let's say Ted traveled approximately 3/4 of the circumference.
So, to find the distance within the face-off circle that Ted traveled, we can multiply the circumference by the fraction he covered:
Distance = (3/4) * C
Distance = (3/4) * π * 15
Now you can use a calculator to find the approximate value.