a 30 mL sample of vinegar is titrated with .1098 M NaOH. it takes 43.28 mL naOH solution to reach the endpoint. Determine the acetic acid concentration in the vinegar solution?

To determine the acetic acid concentration in the vinegar solution, you need to use the concept of stoichiometry and the balanced chemical equation for the reaction between acetic acid (CH3COOH) and sodium hydroxide (NaOH).

The balanced chemical equation for the reaction is:
CH3COOH + NaOH -> CH3COONa + H2O

First, calculate the number of moles of NaOH used in the titration:

Moles of NaOH = Molarity of NaOH × Volume of NaOH solution (in liters)
Moles of NaOH = 0.1098 M × (43.28 mL ÷ 1000 mL/L) (converting mL to L)
Moles of NaOH = 0.1098 × 0.04328

Next, determine the mole ratio between acetic acid and NaOH. From the balanced equation, you can see that 1 mole of acetic acid reacts with 1 mole of NaOH.

Moles of acetic acid = Moles of NaOH

Now, calculate the concentration of acetic acid in the vinegar solution:

Concentration of acetic acid = Moles of acetic acid / Volume of vinegar solution (in liters)
Concentration of acetic acid = (0.1098 × 0.04328) / (30 mL ÷ 1000 mL/L) (converting mL to L)
Concentration of acetic acid = (0.1098 × 0.04328) / 0.03

Finally, solve for the concentration of acetic acid:

Concentration of acetic acid = 0.1098 × 0.04328 / 0.03

Thus, the concentration of acetic acid in the vinegar solution is equal to the calculated value.

To determine the acetic acid concentration in the vinegar solution, you can use the concept of stoichiometry and the equation of the reaction between acetic acid and sodium hydroxide:

CH3COOH + NaOH -> CH3COONa + H2O

First, let's calculate the number of moles of NaOH used in the titration:

moles of NaOH = concentration of NaOH solution * volume of NaOH solution (in liters)
moles of NaOH = 0.1098 mol/L * 0.04328 L
moles of NaOH = 0.004754 mol

According to the balanced equation, the stoichiometric ratio between NaOH and acetic acid (CH3COOH) is 1:1. This means that the number of moles of acetic acid in the vinegar solution is also equal to 0.004754 mol.

Now, we need to find the volume of the vinegar solution that corresponds to the 0.004754 mol of acetic acid. Since the vinegar and NaOH have a 1:1 stoichiometric ratio, their volumes will also be equal.

volume of vinegar solution = volume of NaOH solution = 43.28 mL

However, the given volume of the vinegar solution is 30 mL, which is smaller than the volume required for the titration. Therefore, we need to use this correction factor to calculate the actual concentration of acetic acid.

actual volume of vinegar solution = volume of vinegar solution * (moles of acetic acid / moles of NaOH)
actual volume of vinegar solution = 30 mL * (0.004754 mol / 0.004754 mol)
actual volume of vinegar solution = 30 mL

Finally, we can calculate the acetic acid concentration:

acetic acid concentration = moles of acetic acid / actual volume of vinegar solution (in liters)
acetic acid concentration = 0.004754 mol / (30 mL / 1000)
acetic acid concentration = 0.1585 mol/L

Therefore, the acetic acid concentration in the vinegar solution is approximately 0.1585 mol/L.

This done the same way as the BaSO4 problem.