A total of Rs 14000 is invested for a year , part at 5% and the rest at 6%. If Rs 740 is the total interest , amount invested at 5% is ??
5%-------->X
6%-------->(14000-x)
i1=5%×x×1=5%X
i2=(14000-X)×6%×1
I=i1+i2
I=5%×X×1+(14000-X)×6%×1=10000
Plz solve this question
Rs 14000 is invested for a year, but it seems like the money is having a much better time than I am! Anyway, let's solve this math puzzle.
Let's call the amount invested at 5% 'x'. That means the amount invested at 6% will be Rs 14000 - x.
Now, we need to find the interest earned from these investments. The interest earned from the amount invested at 5% can be calculated as 5% of x (0.05x), and the interest earned from the amount invested at 6% can be calculated as 6% of (14000 - x) (0.06(14000 - x)).
Since the total interest earned is Rs 740, we can set up the equation:
0.05x + 0.06(14000 - x) = 740
Now, let's simplify this equation and find the value of 'x'... but be warned, I might throw in a few fun surprises along the way! *inserts clown wig*
To find the amount invested at 5%, we need to set up a system of equations based on the given information.
Let's assume the amount invested at 5% is x.
Since the total amount invested is Rs 14,000 and the amount invested at 5% is x, the amount invested at 6% is (14000 - x).
The interest earned from the amount invested at 5% is (x * 5%) = 0.05x.
The interest earned from the amount invested at 6% is ((14000 - x) * 6%) = 0.06(14000 - x).
According to the given information, the total interest earned from both investments is Rs 740. So, we can write the equation as:
0.05x + 0.06(14000 - x) = 740
Now, we can solve this equation to find the value of x (the amount invested at 5%).
0.05x + 0.06(14000 - x) = 740
0.05x + 840 - 0.06x = 740
-0.01x = -100
x = (-100) / (-0.01)
x = 10000
Therefore, the amount invested at 5% is Rs 10,000.
amount at 5% --- x
amount at 6% --- 14000
solve for x ....
.05x + .06(14000-x) = 740