Posted by Pamela on .
A ship leaves POrt P and sails 28km away on bearing of 70 degrees to POrt Q. The ship then turns on a bearing of 160 degrees and sails 21km to POrt R. Find angle PQR, calculate the distance PR, Determine the bearing of R from P.
angle PQR = 180 degrees  160 degrees = 20 degrees

math 
Steve,
ships sail on headings, not bearings.
Angle PQR is not the angle between the NS line and R. It is the angle between PQ and QR. That is, 70 + 20 = 90 degrees.
So, now we can figure the xy displacements:
PQ = <28sin70°,28cos70°> = <26.31,9.58>
QR = <21sin20°,21cos20°> = <7.18,19.73>
Add them up and you get PR = <33.49,10.15> = 35.00 at 106.88° 
math 
A ship leaves port and travels 21km on a bearing of 0320and then 45km on a bearing of 2870.(a) Calcu,
Dp yygg