If 23% of the cars that pass by your house each day are red, 12% green, 4% yellow, and 31% black; what is the probability the next car to pass your house will be red or yellow? (Assume every car is only a single color). I have to pick which formula to use. These are the formulas:

Question

If 23% of the cars that pass by your house each day are red, 12% green, 4% yellow, and 31% black; what is the probability the next car to pass your house will be red or yellow? (Assume every car is only a single color). I have to pick which formula to use. These are the formulas:

p(A and B) = p(A) x p(B)

p(A or B) = p(A) + p(B) - p(A and B)

Answer 1

"Red OR Yellow" should be a giveaway.

Here P(A and B)=0 because a red car is not yellow.

P(A)+P(B)=0.12+0.04 = 0.16

Answer 2

To find the probability of the next car being either red or yellow, we will use the formula for the probability of A or B occurring: p(A or B) = p(A) + p(B) - p(A and B).

First, let's find the individual probabilities of the car being red or yellow:

p(A) = probability of a red car = 23%

p(B) = probability of a yellow car = 4%

Now, we need to calculate the probability of both a red and yellow car passing by at the same time:

p(A and B) = probability of a red car and a yellow car = 0% (assuming every car is only a single color)

Now we can plug these values into the formula:

p(A or B) = p(A) + p(B) - p(A and B)
p(A or B) = 23% + 4% - 0%
p(A or B) = 27%

Therefore, the probability that the next car passing your house will be either red or yellow is 27%.