which law of chemical combination is illustrated by the fact that 168 g of fe(iron) reacts with 72 g of water to form 232 g Fe3O4 and 8g H2
Hi r u good at math ireally need help
Law of conservation of mass.
Fe + H2O ==> Fe3O4 + H2
168 + 72 = ...232 + 8
........240 = 240
Matter is noither created nor destroyed.
The law of chemical combination that is illustrated by the given reaction is the Law of Conservation of Mass. According to this law, mass is not created or destroyed during a chemical reaction.
To determine how the Law of Conservation of Mass applies to this reaction, we can calculate the mass of the reactants (iron and water) and compare it to the mass of the products (Fe3O4 and H2).
First, let's find the mass of the reactants:
Mass of iron (Fe) = 168 g
Mass of water (H2O) = 72 g
Now let's find the mass of the products:
Mass of Fe3O4 = 232 g
Mass of H2 = 8 g
Adding up the mass of the reactants:
168 g (Fe) + 72 g (H2O) = 240 g
Adding up the mass of the products:
232 g (Fe3O4) + 8 g (H2) = 240 g
As we can see, the total mass of reactants (240 g) is equal to the total mass of the products (240 g), satisfying the Law of Conservation of Mass. This means that in a chemical reaction, the total mass of the reactants always equals the total mass of the products.