Gabriella wants to tile a room with an area of 320 square feet. The width of the room is 4/5 its length. What are the length and width of the room?
To find the length and width of the room, let's consider the information given. We know that the room has an area of 320 square feet, and the width of the room is 4/5 its length.
Let's start by assuming the length of the room is "x" feet. Therefore, the width of the room would be (4/5)x feet.
The area of the room is the length multiplied by the width. In this case, it would be:
x * (4/5)x = 320 square feet.
To solve this equation, we can multiply the x terms:
(4/5)x^2 = 320.
Next, let's isolate x^2 by dividing both sides of the equation by (4/5):
x^2 = (320 * 5) / 4.
x^2 = 400.
To find the value of x, we can take the square root of both sides of the equation:
x = √400.
x = 20.
Therefore, the length of the room is 20 feet.
Now, let's calculate the width of the room using the information that the width is 4/5 of the length:
Width = (4/5) * length = (4/5) * 20 = 16 feet.
So, the length of the room is 20 feet, and the width of the room is 16 feet.
I’m doing a problem it says “ Isabel wants to estimate the length, width and height of her bedroom. If her bedroom was empty, the volume of her room would be 864 cubic meters. Her bedroom’s length are the same measurements but the height is half the length and width. What are the dimensions of Isabel’s bedroom?”
63
16 and 20
length=x, so width = 4/5 x
(x)(4/5 x) = 320
4x^2 = 1600
x^2 = 400
x = 20
width=4/5 x = 16
check:
16*20 = 320