lader led 5m less of the storing building forming an angle of 60digree on the groud how far bottle of the building?

Someone may be able to help you if you post a question with correct spelling, capitalization and punctuation.

x/5 = cos60°

To find the distance of the bottle from the building, we can use trigonometry. In this case, we have a ladder that is leaning against the building, forming an angle of 60 degrees with the ground.

Let's assume "x" represents the distance of the bottle from the building. Since the ladder is leaning against the building, the distance from the top of the ladder to the ground would be the same as the distance from the bottle to the ground. Let's call this distance "h".

We know that the ladder is 5 meters shorter than the building, so the length of the ladder can be expressed as "x + 5". Using trigonometry, we can relate the sides of the triangle formed by the ladder, the building, and the ground.

In a right triangle, the sine of an angle is equal to the opposite side divided by the hypotenuse. In this case, the opposite side is "h" and the hypotenuse is "x + 5". Therefore, we can write the equation:

sin(60 degrees) = h / (x + 5)

The sine of 60 degrees is √3 / 2, so the equation becomes:

√3 / 2 = h / (x + 5)

To solve for "h", we can rearrange the equation:

h = (√3 / 2) * (x + 5)

Now, we have an expression for "h". Substituting this back into the equation, we get:

√3 / 2 = (√3 / 2) * (x + 5) / (x + 5)

Since (√3 / 2) is a common factor in the numerator and denominator, it cancels out, leaving:

1 = 1

This means that the equation holds true for any value of "x". Therefore, the distance of the bottle from the building can be any value, as long as the ladder is 5 meters shorter than the building and forms an angle of 60 degrees with the ground.