A body P of mass 5kg moving with a velocity of 30M/s collids with another body q moving in opposite direction with a velocity of 20m/s.If the bodies now move in the direction of P at velocity 10m/s.calculate the mass of q
m1×v1+m2×v2 =(m1+m2)
5×30+q+20=(q+5)
150+q×20=q+5=10
collect like terms
150+20+10=2q+5
180=2q×5
180/10=10/10
q=18 kg
Assuming inelastic
m1v1 + m2v2 = (m1+m2)vf
5(30) + m2(-20) = (30+m2)10
Solve for m2
0.15m/s
m1v1=m2v2
5×30=m2×20
m2=150/20
m2=7.5kg
10kg
18 kg
Give me the answer
Give me the answer
10
To calculate the mass of body Q, we can use the principle of conservation of linear momentum. According to this principle, the total linear momentum before the collision is equal to the total linear momentum after the collision.
The linear momentum of an object is given by the product of its mass and velocity, represented by the equation:
Momentum (p) = mass (m) * velocity (v)
Before the collision:
The momentum of body P = mass of P (mP) * velocity of P (vP)
pP = mP * vP
pP = 5kg * 30m/s
pP = 150 kg m/s (momentum of body P)
The momentum of body Q = mass of Q (mQ) * velocity of Q (vQ)
pQ = mQ * vQ
pQ = mQ * (-20m/s) (since Q is moving in the opposite direction)
pQ = -20mQ kg m/s (momentum of body Q)
After the collision:
The momentum of body P = mass of P (mP) * final velocity of P (v'P)
p'P = mP * v'P
p'P = 5kg * 10m/s
p'P = 50 kg m/s (momentum of body P after the collision)
The momentum of body Q = mass of Q (mQ) * final velocity of Q (v'Q)
p'Q = mQ * v'Q
p'Q = mQ * 10m/s (since both bodies move together in the direction of P)
p'Q = 10mQ kg m/s (momentum of body Q after the collision)
According to the principle of conservation of linear momentum:
Initial momentum = Final momentum
(pP + pQ) = (p'P + p'Q)
Substituting the values:
150 kg m/s + (-20mQ kg m/s) = 50 kg m/s + 10mQ kg m/s
Simplifying the equation:
130 kg m/s = -10mQ kg m/s
Dividing both sides of the equation by -10 m/s (to cancel out the velocity term):
130 kg = mQ
Therefore, the mass of body Q (mQ) is equal to 130 kg.