A car leaves a town at 80 kilometers per hour. A second car leaves one hour later. If the second car travels at 125 kilometers per hour, how long will it take the second car to catch up?
80 t = 125 (t-1)
125 = 45 t
t = 2.7777 hours
or 2 hours and 47 min for car 1
and 1 hour and 47 minutes for car 2
check
80 * 2.777 = 222
125 * 1.777 = 222 good
so 1 hour and 47 minutes
To find out how long it will take for the second car to catch up to the first car, we need to determine the time it takes for the distance between them to be zero.
Let's assume that the time taken for the first car to be caught up by the second car is 't' hours.
The first car leaves the town with a speed of 80 kilometers per hour and has a head start of one hour. So, in 't' hours, it would have traveled a distance of 80t kilometers.
The second car is traveling at 125 kilometers per hour, and it starts one hour later than the first car. Hence, it would have traveled a distance of 125(t-1) kilometers in 't' hours.
For the second car to catch up with the first car, their distances should be equal.
So, we can set up the equation:
80t = 125(t-1)
Now, let's solve this equation to find the value of 't':
80t = 125t - 125
125 - 80t = 125
45t = 125
t = 125/45
t ≈ 2.78
Therefore, it will take approximately 2.78 hours for the second car to catch up to the first car.