5. How many grams of iron oxide can be produced from 2.50 g of oxygen reacting with iron, according to the following equation?
2 Fe (s) + 3 O2 (g) -->2 Fe2O3(s)
No that's not right.
mols O2 = 2.50g/32 = 0.078 but you should do it more accurately.
Convert to mols Fe2O3. That's 0.078 x 2/3 = approx 0.052
Then g Fe2O3 = mols x molar mass = 0.052 x 159.7 = approx 8.3.
Calculate the mass of iron needed to completely react with oxygen to produce 5.50 g iron
(TI) oxide.
A Fe + 302
› 2 Fe203
Well, according to my incredibly scientific calculations, if 2.50 g of oxygen reacts with iron according to the equation 2 Fe (s) + 3 O2 (g) -->2 Fe2O3(s), you would end up with exactly enough grams of iron oxide to pick up and bench-press. Just kidding, I'm not really sure. But I can help you with the math if you'd like.
To determine the number of grams of iron oxide produced from 2.50 g of oxygen, you need to use stoichiometry, which is the study of the quantities of substances involved in a chemical reaction.
Step 1: Convert the mass of oxygen to moles.
Since the molar mass of oxygen is 16 g/mol, you can use the following equation to convert grams to moles:
moles of O2 = mass of O2 / molar mass of O2
moles of O2 = 2.50 g / 32.00 g/mol
moles of O2 ≈ 0.0781 mol (rounded to four decimal places)
Step 2: Use the stoichiometric ratio to determine the moles of iron oxide produced.
From the balanced chemical equation, you can see that for every 3 moles of O2, 2 moles of Fe2O3 are produced. Therefore, the mole ratio is:
moles of Fe2O3 = (moles of O2) x (2 moles of Fe2O3 / 3 moles of O2)
moles of Fe2O3 = 0.0781 mol x (2 / 3)
moles of Fe2O3 ≈ 0.0521 mol (rounded to four decimal places)
Step 3: Convert moles of iron oxide to grams.
Since the molar mass of Fe2O3 is 159.69 g/mol, you can use the following equation to convert moles to grams:
grams of Fe2O3 = moles of Fe2O3 x molar mass of Fe2O3
grams of Fe2O3 = 0.0521 mol x 159.69 g/mol
grams of Fe2O3 ≈ 8.32 g (rounded to two decimal places)
Therefore, approximately 8.32 grams of iron oxide can be produced from 2.50 grams of oxygen reacting with iron, according to the given equation.
answered
in order to solve this problem, the best way is to calculate their mole ratio(O2 and Fe2O3).so that would be
mole ratio of O2 and Fe2O3;it would be 3:2=2.50g:x..3X=5 so the mole for fe2o3 is 1.67mol....so u got the mole so find the the mass...formula is moles=mass/Mr(Fe2O3)....1.67mol=mass/272g/mol..thus ur answr comes to 454.24g...therefore the mass o iron oxide comes to 454.24grams..