A 4.96 kg block located on a horizontal frictionless floor is pulled by a cord that exerts a force F=13.7N at an angle theta=16.0degrees above the horizontal. What is the magnitude of the acceleration of the block when the force is applied?

I know a=F/m

the horizontal component of the force is... f cos(Θ)

as you say... a = [f cos(Θ)] / m

To find the magnitude of the acceleration of the block, we can use the formula a = F/m, where a is the acceleration, F is the force applied, and m is the mass of the block.

In this case, the force applied is given as F = 13.7 N (given in the question) and the mass of the block is given as m = 4.96 kg (given in the question).

So, we can substitute these values into the formula:

a = F/m = 13.7 N / 4.96 kg

To calculate this, we divide the force by the mass:

a = 13.7 N / 4.96 kg ≈ 2.76 m/s^2

Therefore, the magnitude of the acceleration of the block when the force is applied is approximately 2.76 m/s^2.