A box of mass m=20kg is to be pushed up the inclined plane by a horizontal force F at constant speed. of μk= 0.2, find the work done on the box by the force F?
What inclined plane?
inclined plane of 15 degree sir
4m length
To find the work done on the box by the force F, we need to calculate the force of friction acting on the box and then multiply it by the distance over which the force is applied.
The force of friction can be calculated using the formula:
- F_friction = μ * N
Where:
- F_friction is the force of friction
- μ is the coefficient of kinetic friction
- N is the normal force
In this case, the box is being pushed up the inclined plane, so the normal force can be calculated as:
- N = mg * cos(θ)
Where:
- m is the mass of the box
- g is the acceleration due to gravity (approximately 9.8 m/s^2)
- θ is the angle of the inclined plane with respect to the horizontal
Given:
- m = 20 kg
- μk = 0.2
Now, let's calculate the normal force N:
- N = 20 kg * 9.8 m/s^2 * cos(θ)
Since the question doesn't provide the value of θ, we need to know the angle of the inclined plane to proceed further.
Once we have the normal force N, we can calculate the force of friction F_friction:
- F_friction = 0.2 * N
To find the work done on the box by the force F, we need to multiply the force of friction by the distance over which the force is applied. However, the distance is not given in the question. Without this information, we cannot determine the work done on the box.