ann is 20 years older than her daughter faye. three years from now she will be six times as old as her daughter. find their present ages
Now 3 years from now
Ann A A+20
Faye 6A 6A+20
My answer is 24 and I'm not sure if it's correct :(
Just check your answer with the "wording" of the question.
First of all it asked for their present ages, so you would need two numbers.
I assume you are saying, that the mother is 24, then the daughter is 4
Three years from now, Mother would be 27 and daughter would be 7
Is 27 six times 7 ??? , no!
ok, let's do it
Let the daughter's present age be x.
(I usually pick x to represent the smaller value)
then the mom would now be x+20
three years from now:
mom --- x+23
daughter x+3
I said: x+23 = 6(x+3)
x+23 = 6x+18
5x = 5
x = 1
the daughter is now 1, and the mom is 21
check:
in 3 years, daughter will be 4
mom will be 24
is 24 six times 4 ? , YES
We have the right answer.
To solve this problem, let's use algebra to represent Ann's and Faye's present ages and then solve for those values.
Let's denote:
Ann's present age as A
Faye's present age as F
We are given that "Ann is 20 years older than her daughter Faye." This can be represented as:
A = F + 20
We are also given that "three years from now, Ann will be six times as old as her daughter." This can be represented as:
A + 3 = 6(F + 3)
Now, we can solve these two equations simultaneously to find the values of A and F.
Using the first equation, we can substitute the value of A in the second equation:
(F + 20) + 3 = 6(F + 3)
Expanding the equation:
F + 23 = 6F + 18
Simplifying the equation:
23 - 18 = 6F - F
5 = 5F
Dividing both sides by 5:
F = 1
Now that we have Faye's present age (F = 1), we can substitute this value back into the first equation to find Ann's present age:
A = F + 20
A = 1 + 20
A = 21
Therefore, Ann's present age is 21 and Faye's present age is 1. Your original answer of Faye's age being 24 is incorrect.