Eric has 48 bills valuing P1,500 to be deposited in a bank. If the bills consistedmof P20
& P50 bills, how many P50 bills does he have?
number of P50 --- x
number of P20 ----48-x
their value:
50x + 20(48-x) = 1500
solve for x
20x+50(48-x)=1500
20x+2400-50x=1500
-30x=1500-2400
-30x=-900
-30 =-30
X=30
To determine the number of P50 bills Eric has, we need to make use of the given information.
Let's assume Eric has x number of P20 bills and y number of P50 bills.
According to the problem, Eric has a total of 48 bills. Therefore, we can write the equation:
x + y = 48 (equation 1)
Additionally, the total value of all the bills is given as P1,500. The P20 bills have a value of 20x, and the P50 bills have a value of 50y. So we can write another equation for the total value:
20x + 50y = 1500 (equation 2)
To solve the system of equations, we can use the substitution or elimination method. Let's use the elimination method:
Multiply equation 1 by 20 to make the coefficients of x in both equations equal:
20x + 20y = 960 (equation 3)
Now subtract equation 3 from equation 2:
(20x + 50y) - (20x + 20y) = 1500 - 960
Simplifying the equation:
30y = 540
Divide both sides of the equation by 30:
y = 18
Therefore, Eric has 18 P50 bills.
To find out how many P50 bills Eric has, we can set up a system of equations based on the information given.
Let's assign variables to the unknowns:
Let x represent the number of P20 bills.
Let y represent the number of P50 bills.
We are given two pieces of information:
1. Eric has a total of 48 bills: x + y = 48.
2. The total value of the bills is P1,500: 20x + 50y = 1500.
Now we can solve these equations simultaneously to find the values of x and y.
First, let's solve the first equation for x:
x = 48 - y.
Now, substitute the value of x into the second equation:
20(48 - y) + 50y = 1500.
Simplify the equation:
960 - 20y + 50y = 1500.
30y = 540.
y = 540 / 30.
y = 18.
Therefore, Eric has 18 P50 bills.