I'm working on a story problem that is using 30-60-90 triangles.
I have to solve for the hypotenuse. The long leg is 6 feet.
So, short leg would be 6 = x square root of 3 /3...Then I'm stuck. I know the hypotenuse is dbl the short leg
as you say, the short leg is
6/√3
so, the hypotenuse is 12/√3
or, they can be written as
2√3 and 4√3
Thank you.
To solve for the hypotenuse in a 30-60-90 triangle, you can apply the properties of this special triangle.
In a 30-60-90 triangle, the ratio of the lengths of the sides is:
Short leg : Long leg : Hypotenuse = 1 : sqrt(3) : 2
Given that the long leg is 6 feet, we can find the short leg using the ratio mentioned above.
Short leg = 6 * sqrt(3) / 3
= 2 * sqrt(3)
Now, to find the hypotenuse, we know that it is twice the length of the short leg.
Hypotenuse = 2 * (2 * sqrt(3))
= 4 * sqrt(3)
Therefore, the hypotenuse of the 30-60-90 triangle is 4 * sqrt(3) feet.