A bowling ball of mass 3.1 kg moves in a
straight line at 2.31 m/s.
How fast must a Ping-Pong ball of mass
2.552 g move in a straight line so that the two balls have the same momentum?
Answer in units of m/s.
To find the speed at which the Ping-Pong ball must move, we need to equate the momentum of both balls.
The momentum of an object is calculated by multiplying its mass by its velocity. Mathematically, momentum (p) can be represented as:
p = m * v
Where p is the momentum, m is the mass, and v is the velocity.
We're given the following information:
For the bowling ball:
Mass (m1) = 3.1 kg
Velocity (v1) = 2.31 m/s
For the Ping-Pong ball:
Mass (m2) = 2.552 g = 0.002552 kg (Note: Remember to convert grams to kilograms for consistency)
Velocity (v2) = ?
We need to find v2, the velocity of the Ping-Pong ball. To calculate it, we'll use the principle of conservation of momentum, which states that the total momentum of a system remains constant unless acted upon by external forces.
Since the momentum of the system must be conserved, we can equate the momentum of the bowling ball and the Ping-Pong ball:
m1 * v1 = m2 * v2
Plugging in the known values, we have:
3.1 kg * 2.31 m/s = 0.002552 kg * v2
To isolate v2, divide both sides of the equation by 0.002552 kg:
v2 = (3.1 kg * 2.31 m/s) / 0.002552 kg
Calculating this expression, we find:
v2 ≈ 2809.29 m/s
So, the Ping-Pong ball must move at a speed of approximately 2809.29 m/s in a straight line in order to have the same momentum as the bowling ball.
Is the bowling ball rolling?
is the ping pong ball rolling?
Rolling KE is different that transnational KE.