the side of a triangle are 7,16,18. find the longest side of a similar triangle whose shortest side is 7.5.
So, Since the sides we have of Triangle A are 7,16,18. And the shortest of Triangle B is 7.5. We know that 7 & 7.5 are similar sides then. So 7.5/7 = 1.07142. Then, 18*1.07142 = 19.28556. Or rounded to be 19.29 units, that is your answer. Hoped it helped! :)
Or 7.5/7 = x/18, X = ?.
To find the longest side of a similar triangle, we need to establish a proportional relationship between the corresponding sides of the two triangles.
In this case, we want to find the longest side of the similar triangle when the shortest side is 7.5. Let's assume that the longest side of the similar triangle is 'x'.
We can set up a proportion using the corresponding sides of the two triangles:
7/7.5 = 18/x
To solve for 'x', we can cross-multiply and then divide:
7x = 7.5 * 18
x = (7.5 * 18)/7
Calculating the expression on the right side gives us:
x ≈ 19.286
Therefore, the longest side of the similar triangle, when the shortest side is 7.5, is approximately 19.286.