If 238U92 emits successively four alpha particles two beta particles, what will be the atomic number and mass number of the final product.
... and not a single thought or attempt of your own. =(
Oh please. What are an alpha particle and a beta particle? Then do the subtraction.
To determine the atomic number and mass number of the final product, we need to understand the process of radioactive decay in which 238U92 emits alpha and beta particles.
An alpha particle consists of two protons and two neutrons, which means it has an atomic number of 2 and a mass number of 4. A beta particle can either be an electron (β-) or a positron (β+), but in this case, let's assume it's an electron.
238U92 decaying into four alpha particles means that it will lose four sets of alpha particles, resulting in a new element. Each alpha particle emitted will decrease the atomic number by 2 and the mass number by 4.
Since four alpha particles are emitted, the atomic number will decrease by 2 x 4 = 8, and the mass number will decrease by 4 x 4 = 16.
238U92 - 4(2He4) = 226Rn86
The atomic number of the final product, 226Rn86, will be 86, and the mass number will be 226.