(〖3x〗^4/〖6x〗^3 )2
I'm having some trouble solving this. In the numerator is 3x to the 4th. In the denominator is 6x to the 3rd. All of that is in a bracket and it's all squared.
Do I have to first subtract the exponents, 4 - 3 and then multiply by the 2 exponent? I'm a little lost here.
Thank you.
The simplification process starts
inside the expression:
((3x)^4/(6x)^3)^2 =
(81x^4/216x^3)^2 = (3x/8)^2 = 9x^2/64.