How do you find the point of intersection(s) for x = 2y2 + 3y + 1 and 2x + 3y2 = 0
A) You cannot find points of intersections for non-functions.
B) Plug in 0 for x into both equations and solve for y. Then plug that answer back into the other equation to find the corresponding x-coordinate.
C) Solve both equations for x and set them equal to each other. This will give you the y-coordinates of the points of intersection. Then plug back into one of the equations to find the corresponding x-coordinates.
D) Solve both equations for y and set them equal to each other. This will give you the x-coordinates of the points of intersection. Then plug back into one of the equations to find the corresponding y-coordinates.
*******I think the answer is C******
Yes, you are correct. The correct answer is C) Solve both equations for x and set them equal to each other. This will give you the y-coordinates of the points of intersection. Then plug back into one of the equations to find the corresponding x-coordinates.
Correct! The answer is C) Solve both equations for x and set them equal to each other. This will give you the y-coordinates of the points of intersection. Then plug back into one of the equations to find the corresponding x-coordinates.
To find the point(s) of intersection between the two equations, we can start by setting the expressions for x in both equations equal to each other.
First, let's solve for x in the equation x = 2y^2 + 3y + 1. Rearranging this equation, we get:
x - 2y^2 - 3y - 1 = 0
Next, let's solve for x in the equation 2x + 3y^2 = 0. Rearranging this equation, we get:
2x = -3y^2
x = -3y^2/2
Now that we have both equations in terms of x, we can set them equal to each other:
x - 2y^2 - 3y - 1 = -3y^2/2
To simplify, we can multiply both sides of the equation by 2 to eliminate the fractions:
2(x - 2y^2 - 3y - 1) = -3y^2
Expanding and rearranging, we get:
2x - 4y^2 - 6y - 2 = -3y^2
Combining like terms:
2x + 3y^2 - 6y - 2 = 0
Now, we have a quadratic equation in terms of y. We can solve this equation to find the y-coordinates of the points of intersection. Once we have the y-values, we can plug them back into one of the original equations to find the corresponding x-values.
Therefore, the correct answer is C) Solve both equations for x and set them equal to each other. This will give you the y-coordinates of the points of intersection. Then plug back into one of the equations to find the corresponding x-coordinates.