Two point charges objects produce an electric force on each other of 3.6x10^-2 N. What is the electric force between them if the distance is increased five times?
since the force is inversely proportional to d^2, it will be reduced by a factor of 25.
To find the electric force between two point charges, we need to use Coulomb's Law. The formula for Coulomb's Law is:
F = k * (q1 * q2) / r^2
Where:
F is the electric force between the charges,
k is Coulomb's constant (9 x 10^9 Nm^2/C^2),
q1 and q2 are the magnitudes of the charges, and
r is the distance between the charges.
In this case, we are given the force (3.6x10^-2 N) and asked to find the force when the distance is increased by five times. Let's call the initial distance d, and the new distance 5d.
Using Coulomb's Law, we can write the equation for the initial force as:
3.6x10^-2 N = k * (q1 * q2) / d^2
To find the new force, we need to find the relationship between the initial and new distances. The new distance is five times the initial distance, so:
5d = 5 * d
We can substitute 5d into the equation for Coulomb's Law:
F = k * (q1 * q2) / (5d)^2
Simplifying this equation gives:
F = k * (q1 * q2) / 25d^2
So, the new electric force between the charges is F/25.
To calculate this force, we need to know the values of the charges (q1 and q2). If you provide the magnitudes of the charges, we can use these values to calculate the new force.