find the constant force necessary to accelerate a car of mass 1000kg from 15m/s to 20m/s in 10s against resistance of 270N ? pls show work (answer is 770N just in case to check)
First find a:
20 = 15 + a(10)
a = 0.5
F = ma + resistance = 1000(.5) +270
To calculate the constant force required to accelerate a car, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a). In this case, the acceleration can be calculated using the initial velocity (vi), final velocity (vf), and time (t) taken to reach that velocity.
Given:
Mass (m) = 1000 kg
Initial velocity (vi) = 15 m/s
Final velocity (vf) = 20 m/s
Time (t) = 10 s
Resistance force (fr) = 270 N
First, calculate the acceleration (a) using the formula:
a = (vf - vi) / t
a = (20 - 15) / 10
a = 5 / 10
a = 0.5 m/s^2
Since there is resistance, the net force (Fnet) acting on the car is the sum of the driving force (Fdrive) and the resistance force (fr). The driving force is equal to mass multiplied by acceleration:
Fdrive = m * a
Fdrive = 1000 * 0.5
Fdrive = 500 N
Finally, to find the constant force required to overcome resistance and accelerate the car, we need to subtract the resistance force from the driving force:
F = Fdrive - fr
F = 500 - 270
F = 230 N
Therefore, the constant force necessary to accelerate the car is 230 N, not 770 N as mentioned. Double-check your calculations to verify the correct answer.