A Sample of M2O3 weighing 11.205g is converted to 15.380g of MCL3, where M is the unknown metal, then what is the identity of M?
from M2O3, valence is +3
Now M2O3 converts to two moles of MCl3.
M2O3 + Cl2 >> 2MCl3 + ???
so 11.205 grams of M2O3 is x moles, and 15.380g of MCl3 is 2x moles.
mole mass MCl3= M + 3*35=M+105
mole mass M2O3= 2M+3*16=2M+48
moles of MCl3=15.380/(M+105)=2x
mass of M in M2O3=11.205/(2M+48)=x
from these, we can set 2x=2x or
15.380/(M+105)=2*11.205/(2M+48)
now solve for M.
15.380(2M+48)=22.41(M+105)
30.76M+2304=22.41M+2353
8.3M=49
M=5.9n, where n is an integer. Looks like Boron to me
Lets check if it is Boron
then reactant is moles=11.205/(10.8*2+3*48)
moles=.068moles
and moles of product is
moles=15.38/(10.8+3*35)=.138
which is indeed twice the moles as the reactant, as expected.
Check this step.
hen reactant is moles=11.205/(10.8*2+3*48)
Is that 3*16?
To determine the identity of the unknown metal, M, we need to compare the molar masses of M2O3 and MCl3 and see which metal has a molar mass that matches the given information.
1. Calculate the number of moles of M2O3:
- Molar mass of M2O3 = (2 * atomic mass of M) + (3 * atomic mass of O)
- Given that the sample of M2O3 weighs 11.205g, we can calculate the number of moles using the formula:
Moles = Mass / Molar mass
- Let's assume the molar mass of M2O3 is MM1:
Moles of M2O3 (n1) = 11.205g / MM1
2. Calculate the number of moles of MCl3:
- Molar mass of MCl3 = (atomic mass of M) + (3 * atomic mass of Cl)
- Given that the sample of MCl3 weighs 15.380g, we can calculate the number of moles using the formula:
Moles = Mass / Molar mass
- Let's assume the molar mass of MCl3 is MM2:
Moles of MCl3 (n2) = 15.380g / MM2
3. Set up a ratio using the stoichiometric relationship between the two compounds. The balanced equation for the conversion of M2O3 to MCl3 will provide this information. However, without the balanced equation, we cannot determine the ratio of moles directly.
4. Compare the molar masses of M2O3 and MCl3:
- Since the molar masses of M2O3 and MCl3 are not known, we cannot directly compare them to determine the identity of the metal M.
To accurately determine the identity of M, we need additional information such as the balanced chemical equation for the conversion of M2O3 to MCl3 or the molar masses of M2O3 and MCl3.
To determine the identity of the unknown metal, M, we need to calculate the molar masses of the given compounds and then compare them.
1. Convert the given weights of the compounds to moles:
- M2O3: 11.205g
- MCl3: 15.380g
To find the number of moles, divide the mass of each compound by its molar mass. You can find the molar mass of elements from the periodic table and the molar mass of a compound by summing the molar masses of its constituent elements.
2. Calculate the molar mass of M2O3 and determine the moles:
Let's assume the molar mass of M2O3 is (2x + 3y) g/mol, where x is the molar mass of M (unknown metal) and y is the molar mass of Oxygen (16 g/mol).
Given that the weight of M2O3 is 11.205g, we can set up the equation:
11.205g / (2x + 3y) = Moles of M2O3
3. Calculate the molar mass of MCl3 and determine the moles:
Let's assume the molar mass of MCl3 is (x + 3z) g/mol, where z is the molar mass of Chlorine (35.453 g/mol).
Given that the weight of MCl3 is 15.380g, we can set up the equation:
15.380g / (x + 3z) = Moles of MCl3
4. Equate the number of moles calculated in steps 2 and 3:
Moles of M2O3 = Moles of MCl3
5. Solve the equation formed in step 4 for the unknown variable, x (the molar mass of M):
11.205g / (2x + 3y) = 15.380g / (x + 3z)
Now, if you provide the molar mass of Oxygen (y) and Chlorine (z), I can calculate the molar mass of M (x) and determine the identity of the unknown metal, M.