Half of the sum of three times a number and an another number is twice the first number.
What is your question?
Also lacking data.
Let's break down the information provided step by step to understand it better.
First, let's assign variables to the unknowns mentioned in the problem to help us solve it. Let's call the first number "x" and the other number "y."
The problem states that the sum of three times a number (x) and another number (y) is involved. So we can begin by writing an equation to represent this:
3x + y
The problem states that "half of the sum" is involved. To find half of a sum, we divide it by 2. Therefore, the equation becomes:
(3x + y)/2
Now, the problem indicates that this expression is equal to twice the first number (2x). So we can set up the equation:
(3x + y)/2 = 2x
To solve the equation and find the values of x and y, we need to isolate the variables on one side.
Multiplying through by 2 will help us eliminate the denominator:
3x + y = 4x
Next, let's bring all the terms with 'x' to one side:
3x - 4x + y = 0
Simplifying this gives:
-y = -x
Or, multiplying through by -1:
y = x
Therefore, we've found that the two variables, x and y, are equal. This means that any value for 'x' will also be the value for 'y'. So the pair (x, y) can be represented as (x, x).
To summarize, the solution to the problem is that the two numbers are equal. In other words, if you choose any value for 'x', the value for 'y' would be the same.