A force of 20N act an object angle of 30 to the unclined plane the object move 8.0m up the unclined plane. What is the workdone by the force plz draw.
To find the work done by a force acting on an object, we can use the formula:
Work = Force x Distance x cos(θ)
Where:
- Work is the work done (in joules, J)
- Force is the magnitude of the force applied (in newtons, N)
- Distance is the distance over which the force is applied (in meters, m)
- θ is the angle between the force and the direction of motion (in degrees)
Given:
- Force = 20N
- Distance = 8.0m
- θ = 30°
Now, let's calculate the work done:
Work = 20N x 8.0m x cos(30°)
To find the cosine of 30°, we can use a scientific calculator or refer to a trigonometric table. The cosine of 30° is approximately 0.866.
Work ≈ 20N x 8.0m x 0.866
Work ≈ 138.56 J
Therefore, the work done by the force is approximately 138.56 joules.
As for drawing the diagram, I can describe it verbally:
Draw a line representing the inclined plane, slanting upward. On this line, draw an arrow pointing upward at an angle of 30 degrees from the horizontal. Label this arrow as "20N" to indicate the force applied. Finally, draw an arrow pointing along the inclined plane, going upward for a distance of 8.0m. Label this arrow as "8.0m" to represent the distance traveled by the object along the inclined plane.