Silver chloride was formed when 10.10g of silver trioxonitrate(v) reacts with 14.10g of sodium chloride to form 9.58g of sodium trioxonitrate(v),write out the balance equation
AgNO3 + NaCl ==> AgCl + NaNO3.
You quote all of those numbers BUT ask only for the equation. Two observations.
1.This is a limiting reagent problem if you want to do the math and determine the amount of AgCl formed.
2. I call that silver nitrate and sodium nitrate. In my book trioxonitrate(V) is gibberish.
14.62g
To write out the balanced equation for the reaction, we need to determine the chemical formulas of the compounds involved and balance the number of atoms on both sides of the equation.
Given:
Mass of silver trioxonitrate(V) (AgNO3) = 10.10g
Mass of sodium chloride (NaCl) = 14.10g
Mass of sodium trioxonitrate(V) (NaNO3) = 9.58g
First, we need to convert the given masses into moles by using the molar mass of each compound.
Molar mass of AgNO3:
Ag = 107.87 g/mol
N = 14.01 g/mol
O = 16.00 g/mol (x3 since there are three oxygen atoms in the compound)
Total molar mass = 169.87 g/mol
Moles of AgNO3 = Mass / Molar Mass
Moles of AgNO3 = 10.10g / 169.87 g/mol = 0.0594 mol
Molar mass of NaCl:
Na = 22.99 g/mol
Cl = 35.45 g/mol
Total molar mass = 58.44 g/mol
Moles of NaCl = Mass / Molar Mass
Moles of NaCl = 14.10g / 58.44 g/mol = 0.241 mol
Molar mass of NaNO3:
Na = 22.99 g/mol
N = 14.01 g/mol
O = 16.00 g/mol (x3 since there are three oxygen atoms in the compound)
Total molar mass = 85.00 g/mol
Moles of NaNO3 = Mass / Molar Mass
Moles of NaNO3 = 9.58g / 85.00 g/mol = 0.113 mol
Now, let's figure out the balanced equation based on the stoichiometry of the reaction:
AgNO3 + NaCl → AgCl + NaNO3
The balanced equation is:
2 AgNO3 + 2 NaCl → 2 AgCl + 2 NaNO3