the ones digit of 2-digit number is twice
the tens digit when the number formed by reversing the digit is added to the original number . The sum is 99 . find the original ?
tens digit --- x
unit digit ---- 2x
the actual number = 10x + 2x = 12x
the number reversed = 10(2x) + x = 21x
12x + 21x = 99
33x = 99
x = 3
the original number was 63