A boy is 10yrs old,his mother is 37yrs old,in how many years' time will the mother be twice her son's age
2(10+x) = 37+x
In seventeen years time
17
To determine in how many years' time the mother will be twice her son's age, we can set up an equation.
Let's assume that the number of years we're looking for is "x."
Currently, the boy is 10 years old, so in x years, he will be 10 + x years old.
Similarly, the mother is 37 years old, so in x years, she will be 37 + x years old.
Setting up the equation:
37 + x = 2(10 + x)
Now, we can solve this equation to find the value of x.
Expanding the equation:
37 + x = 20 + 2x
Rearranging the equation:
x - 2x = 20 - 37
Simplifying:
-x = -17
Multiplying both sides by -1 to isolate x:
x = 17
Therefore, in 17 years' time, the mother will be twice her son's age.