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What is the squareroot of -4
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http://www.google.com/#q=squareroot+of+-4
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A couple of extra practice questions I can't remember how to do. Can anyone help?
1. "2*squareroot*5(3*squareroot*7 +
Top answer:
Ok for number one i can't follow your logic, but you have to solve the problem in the brackets
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find the standard form of the complex number shown below
9(cos 11pi/6 + isin 11pi/6) a. 2/9 - 2(squareroot)3/9 i b.
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just evaluate, even if you don't have a calculator, you should be able to find cos 11π/6 or cos
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^5 squareroot of x^20
*my answer x^4 ^3 squareroot of 729/343 my answer: couldn't figure it out use rational exponents to write
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^3squareroot of 729/343 you can use your calculator to figure this out and you will get 9/7. the
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write the expression in the form bi, where b is the real number
squareroot-16 squareroot-25 squareroot-3 squareroot-5
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what is 4i squared? 5i?
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Classify each statement as sometimes, always, or never true.
A. 2^(2/3)*4^(4/3)=8*2^(1/3) B. If x>0, then (squareroot
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To classify each statement as sometimes, always, or never true, we will analyze each statement
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find a unit vector in the direction of u
u = (-5, -12, 9) a. (-5, -12, 9) b. 1 / squareroot 26 (-5, -12, 9) c. squareroot 26 (-5,
Top answer:
5^2 + 12^2 + 9^2 = 250 length = sqrt 250 = 5 sqrt 10 so (1 / 5sqrt10) (-5,-12,9)
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Simplify:
1.SquareRoot(-144) 2.SquareRoot(-64x^4) 3.SquareRoot(-13)*SquareRoot(-26) 4.(-2i)(-6i)(4i) 5. i^13 6. i3^8 7.(5 – 2i)
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You have far too many questions for one post, both for this post and the later one. your chances of
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I need some help figuring these.
Compute each product and simplify the result. I don't have the squareroot sign so put that
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To solve these problems, we need to simplify each expression by performing the indicated operations.
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I need some help figuring these.
Compute each product and simplify the result. I don't have the squareroot sign so put that
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1. 0.45 2. 4sqt5 +9 3. -6sqt10 -75 4. 13sqt3 + 7sqt30
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Determine whether the triple of numbers can be the sides of a right triangle. Please explain.
6, 8, 10 Squareroot of 2,
Top answer:
If it is a right-angled triangle, then clearly the largest number would have to be the hypotenuse.
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Evaluate limit squareroot of (x^4 - 16)/(x^3 - 8) as x approaches 2
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Is the ans (0.0256/25)= 0.001024 Squareroot of 0.001024 = 0.032
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find the area of the region enclosed by y=squareroot of x, the line tangent to y= squareroot of x at x=4 and the x-axis
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im doing solving radical equations
how do i do the squareroot of x+1=x+1 the squareroot is only around the first x+1 i got to the
The problem is lim --> 2 for g(x) which is 2((x-2/(squareroot x)-2)) I just substituted 2 in for x and 2((2-2)/(squareroot 2)-2)
The problem is lim --> 2 for g(x) which is 2((x-2/(squareroot x)-2)) I just substituted 2 in for x and 2((2-2)/(squareroot 2)-2)
The problem is lim --> 2 for g(x) which is 2((x-2/(squareroot x)-2)) I just substituted 2 in for x and 2((2-2)/(squareroot 2)-2)
