Please I need some help for this problem below please show the full solution thanks:Two angles of a triangle have the same measure and the third one is 51 degrees greater than the measure of each of the other two. Find the measure of the LARGEST angle in the triangle.
3x + 51 = 180
3x = 129
x = 43
43 + 51 = ?
Thank you sue
43+51=94
You're welcome, Seymour/Arie.
Please use the same name for your posts.
To find the measure of the largest angle in the triangle, we need to use the fact that the sum of angles in a triangle is always 180 degrees.
Let's start by assuming that the two angles with the same measure are both x degrees. We can then determine the measure of the third angle.
According to the problem, the third angle is 51 degrees greater than the measure of each of the other two angles. Therefore, the third angle would be (x + 51) degrees.
Using the fact that the sum of angles in a triangle is 180 degrees, we can set up the equation:
x + x + (x + 51) = 180
Simplifying the equation, we get:
3x + 51 = 180
Subtracting 51 from both sides, we have:
3x = 129
Dividing both sides by 3, we find:
x = 43
Now that we know the value of x, we can substitute it back into the equation to find the measure of the third angle:
x + 51 = 43 + 51 = 94
Therefore, the measure of the largest angle in the triangle is 94 degrees.