How many moles of oxygen will be produced by 0.27 moles of potassium chlorate?

2 KCLO3 = 3 O2 + 2 KCL

0.27 x 3 O2 / 2KCL = 0.405?

0.27 x 3 O2 / 2KCLo3(potassium chlorate) = 0.405

Yes.

To determine the number of moles of oxygen produced by 0.27 moles of potassium chlorate, we can use the given balanced chemical equation:

2 KClO3 -> 3 O2 + 2 KCl

From the equation, we can see that for every 2 moles of potassium chlorate (KClO3), 3 moles of oxygen (O2) are produced.

Let's use a proportion to find the number of moles of oxygen produced:

(0.27 moles KClO3) x (3 moles O2 / 2 moles KClO3) = 0.405 moles O2

So, according to the balanced equation, 0.27 moles of potassium chlorate will produce 0.405 moles of oxygen.