I am an even. number the sum of my digits equals 7. I am greater than 40 and less than 50. what number am I?
42, 44, 46, 48
None of those numbers meets your criteria.
7 = 1+6 2+5 3+4
if greater than 40 and less than 50, has to start with 4
impossible to be an even number
43
To find the number you are, we can start by listing the even numbers between 40 and 50: 42, 44, 46, 48.
Now we need to check that the sum of the digits of each number equals 7:
For the number 42, the sum of the digits is 4 + 2 = 6, which is not equal to 7.
For the number 44, the sum of the digits is 4 + 4 = 8, which is not equal to 7.
For the number 46, the sum of the digits is 4 + 6 = 10, which is not equal to 7.
For the number 48, the sum of the digits is 4 + 8 = 12, which is not equal to 7.
So, there is no even number greater than 40 and less than 50 where the sum of its digits is equal to 7. Therefore, there is no number that satisfies all the given conditions.
To find the number that satisfies these conditions, we can use a systematic approach.
We know that the number is an even number, greater than 40 and less than 50, and the sum of its digits equals 7.
Let's start by listing all even numbers between 40 and 50: 42, 44, 46, 48.
Now we need to calculate the sum of the digits for each of these numbers:
For 42: 4 + 2 = 6
For 44: 4 + 4 = 8
For 46: 4 + 6 = 10
For 48: 4 + 8 = 12
Since none of these numbers have a digit sum equal to 7, none of them satisfy the given conditions.
Therefore, there is no number that is an even number, greater than 40 and less than 50, and has a digit sum equal to 7.