Questions LLC
Login
or
Sign Up
Ask a New Question
Science
Physics
is the mechanical energy of a teflon coated block sliding down a rough incline remaining constant?
1 answer
only if its speed is constant.
You can
ask a new question
or
answer this question
.
Similar Questions
a block slides down an angle 10 incline at a constant speed. what is the coefficient of sliding friction between the block's
Top answer:
Since there is no acceleration, the friction force, M g u cos 10, equals the component of the weight
Read more.
.: A 5.0 kg block is moving with constant velocity down a rough incline plane. The coefficients of static and kinetic friction
Top answer:
gravity down the plane: mgSinTheta normal to the plane weight: mgCosTheta constant velocity, no
Read more.
A 19.62 kg block is sliding down a 34.52 degree incline at a constant velocity. What is the mu k of kinetic friction between the
Top answer:
constant velocity means no acceleration. So, that means that the frictional force exactly cancels
Read more.
Starting from rest, a 5.0 kg block slides 2.5 m down a rough 30.0 degrees incline in 2.0s. Determine (a) the work done by the
Top answer:
a is Fnet = F
Read more.
A block slides on a rough 45 degree incline .the coefficient of friction the block and incline is µk. what is the ratio of
Top answer:
it is the same, force diagram is the same, acceleration depends on forces. the only thing different
Read more.
A 2kg block situated on a rough incline is connected to a spring of negligible mass having a spring constant of 100N/m. The
Top answer:
To find the coefficient of kinetic friction between the block and inclined plane, we can use the
Read more.
A 3.0 kg block is moved up a 37 incline under a constant horizontal force of 40.0 N. The coefficient of friction is 0.10 and the
Top answer:
casdca
Read more.
A 3.0 kg block is moved up a 37 degree incline under a constant horizontal force of 40.0 N. The coefficient of friction is 0.10
Top answer:
Wb = m*g = 3kg * 9.8N/kg = 29.4 N. = Weight of block. Fp = 29.4*sin37 = 17.69 N. = Force parallel to
Read more.
A 3.0 kg block is moved up a 37 degree incline under a constant horizontal force of 40.0 N. The coefficient of friction is 0.10
Top answer:
Work is done on the block therefore kinetic energy is 1/2mv^2. Identify the object - Block Win or Wo
Read more.
A block slides down a 10 angled incline at a constant speed. what is the coefficient of sliding friction between the blocks
Top answer:
nevermind, someone helped me earlier
Read more.
Related Questions
At the top of a frictionless inclined plane, a .50 kilogram block of ice possesses 6.0 joules of gravitational potential energy
A track consists of a frictionless incline plane, which is a height of 0.5m, and a rough horizontal section with a coefficient
A block of mass 11 kg is at rest on a rough plane inclined at 30° to the horizontal. A force acts on the block in a direction
10. A 3 kg block moves up a 40° incline with constant speed under the action of a 26N force acting up and parallel to the
A 0.50-kg block, starting at rest, slides down a 30.0° incline with kinetic friction coefficient 0.30 (the figure below). After
a block moves up 45degree incline w/ constant speed under the action of a force of 15n applied parallel to the incline.If the
Starting from rest, a 5.00 kg block slides 2.50 m down a rough 30.0 degree incline. The coefficient of kinetic friction between
the block is acted upon by its W=200 lb, a horizontal force Q=600 lb, and the pressure P exerted by the inclined plane. The
Two blocks of masses m1 = 4.4 kg and m2 = 4.8 kg are connected by a string as shown in the figure above. Block 1 moves at a
A block-spring system oscillates with an amplitude of 3.50 cm. The spring constant
is 250 N/m and the mass of the block is 0.500
