What would be the average velocity of an object falling 1.25m from the rest?
Vf^2=Vi^2+2ad
Vf^2=0^2+2(9.8)(1.25)
4.94974
To find the average velocity of an object falling from rest, you need to know the time it takes to fall the given distance. Since you haven't provided the time, we can calculate it using the equation of motion for free fall.
In free fall, the vertical distance an object falls is given by the equation:
h = (1/2) * g * t^2
Where:
h = vertical distance (1.25 m)
g = acceleration due to gravity (roughly 9.8 m/s^2)
t = time taken to fall
Rearranging the formula to solve for t:
t = sqrt((2 * h) / g)
Substituting the given values:
t = sqrt((2 * 1.25) / 9.8) ≈ 0.503 s
Now that we have the time, we can calculate the average velocity using the formula:
average velocity = total displacement / time
Since the object falls vertically downwards, the total displacement is equal to the given distance (1.25 m). Therefore:
average velocity = 1.25 m / 0.503 s ≈ 2.483 m/s
So, the average velocity of the object falling 1.25 m would be approximately 2.483 m/s.