If 59 J of heat is added to an aluminum can with a mass of 22.2 g , what is its temperature change? Specific heat capacity of aluminum is 0.903 J/g∘C.
q = mass Al x specific heat x (Tfinal-Tinitial)
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To determine the temperature change of the aluminum can, we need to use the formula:
q = m × c × ΔT
Where:
- q is the amount of heat energy transferred
- m is the mass of the substance (in grams)
- c is the specific heat capacity of the substance (in J/g∘C)
- ΔT is the change in temperature (in ∘C)
In this case, we are given:
- q = 59 J
- m = 22.2 g
- c = 0.903 J/g∘C
We need to rearrange the formula to solve for ΔT:
ΔT = q / (m × c)
Substituting the given values:
ΔT = 59 J / (22.2 g × 0.903 J/g∘C)
Now, we can calculate the temperature change:
ΔT = 2.64 ∘C
Therefore, the temperature change of the aluminum can is 2.64 degrees Celsius.