This is my question every one . Please help me have it already I had 6 as my answer. In a class of 50 student 28,22,20 of them offer physics,chemistry and biology respectively also 4 of them offer physics and chemistry but not biology,3 offer physics and biology but not chemistry,6 offers biology and chemistry but not physics if 13 of them offers physics only find number of student how offers all subject

I sketched a Venn diagram

Looking at the diagram (you need to do this also)
28physics-4(PandC, not B)-3(PandB, not C)-P,C,B-13(p only)

so if my math is right
P,C,and B=28-4-3-13=8

The answer is 1

To find the number of students who offer all three subjects, we can use a Venn diagram to visualize the given information.

Let's start by labeling the three overlapping circles representing physics, chemistry, and biology.

Based on the given information:
- Out of the 50 students, 28 offer physics, 22 offer chemistry, and 20 offer biology.
- 4 students offer physics and chemistry but not biology.
- 3 students offer physics and biology but not chemistry.
- 6 students offer biology and chemistry but not physics.

Since the total number of students offering physics only is 13, we can infer that the remaining students who offer physics must also offer the other subjects. Therefore, the number of students who offer all three subjects can be calculated as follows:

Total number of students taking physics = Students taking physics only + Students taking physics and chemistry but not biology + Students taking physics and biology but not chemistry + Students taking all three subjects
28 = 13 + 4 + 3 + Students taking all three subjects

By rearranging the equation, we can solve for the number of students who offer all three subjects:

Students taking all three subjects = 28 - (13 + 4 + 3) = 28 - 20 = 8

Therefore, the number of students who offer all three subjects is 8.