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Mathematics
Algebra
Sequences and Series
In a sequence given by Tn = a + b bn the 6th and 13th terms are 22 and 71 respectively. Find the values of a and b.
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just did it, look back
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In a sequence given by Tn = a + b bn the 6th and 13th terms are 22 and 71 respectively. Find the values of a and b.
Top answer:
done when you posted this under a different name. look at your other post.
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The 14th term of an A.P is 864,while 25th term is 1557 find the ,19th term,sum of 13th and 56th terms,product of 6th and 13th
Top answer:
a14 = a1 + 13 d = 864 a25 = a1 + 24 d = 1557 a25 - a14 a1 + 24 d = 1557 - a1 + 13 d = 864
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The 14th term of an A.P is 96,while 25th term is 173 find the ,19th term,sum of 13th and 56th terms,product of 6th and 13th
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You are just using the standard definitions here: 14th term --> a + 13d = 96 25th term --> a + 24d =
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The 14th term of an A.P is 96,while 25th term is 173 find the ,19th term,sum of 13th and 56th terms,product of 6th and 13th
Top answer:
Well, if I were an arithmetic progression, I would probably be the "Slowly Running Out of Jokes"
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The 1st, 5th and 13th terms of an arithmetic sequence are the first three terms of a geometric sequence with a common ratio 2.
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My answer is 12276, is this correct?
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The 6th and the 13th term of a GP are 24 and 3 by 16 respectively find the sequence
Top answer:
T13/T6 = ar^12/ar^5 = r^7 (3/16)/24 = 1/128 = (1/2)^7 so, ...
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The 14th term of an arithmetic progression AP is 96 while the 25th term is 173.find the
A: 19th terms B:sum of 13th and 53 terms
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what have you done so far?
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The 6th and 13th term of a geometric progression are 24 and 3/16 respectively.Find the sequence.
Top answer:
clearly, d = (3/16 - 24)/7 = -381/112 Now you can find a, since a+5d = 24 Now you can list the terms
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The 1st,5th,13th term of an arithmetic sequence are the first 3 terms of geometric sequence with a common ratio of 2. If the
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Why don't we call the first term of the arithmetic sequence "a" and the common difference "d"? That
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The 13th termof an arithmetic sequence is 61 and the 20th term of the squence is 82. Calculate the sum of the first 25 terms of
Top answer:
T13 = a+12d = 61 T20 = a+19d = 82 so, T20-T13 = 7d = 21 d = 3 a = 25 S25 = 25/2 (25 + 25+24*3) =
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