An aluminum sheet used for food preservation weighs about 0.05 g/cm-2 How many electrons are in a 1 cm2 of this sheet?

Each atom of aluminum has 13 electrons.

electrons=13*atomsAl
= 13*avagNumber*molesAL
= 13*6.022E23(.05g/cm^2*1cm^2/27)

To calculate the number of electrons in a 1 cm2 aluminum sheet, we need to consider the molar mass of aluminum and Avogadro's number.

1. Determine the molar mass of aluminum: The atomic mass of aluminum (Al) is approximately 26.98 g/mol.

2. Calculate the number of moles of aluminum in 0.05 g of aluminum:

Number of moles = Mass / Molar mass
= 0.05 g / 26.98 g/mol

3. Use Avogadro's number to calculate the number of atoms of aluminum:

Number of atoms = Number of moles × Avogadro's number
= Number of moles × (6.022 × 10^23 particles/mol)

Since each aluminum atom has 13 electrons, we can consider this as the number of electrons.

4. Finally, multiply the number of electrons per atom by the number of atoms in 1 cm2:

Number of electrons = Number of atoms × 13 electrons/atom

Follow these steps to calculate the number of electrons in a 1 cm2 aluminum sheet used for food preservation.