Write y=-2/5x-3 in standard form using integers.
2x+5y=-15
2x+y=-3
2x+5y=-3
x+y=-15
1st step: clear the fraction by multiplying by 5:
5y = -2x-3
Now you finish it up.
could you at least tell me the steps i would take to finish it up
all you have to do is rearrange terms so that the equation is in the form
Ax + By = C
Can you not figure out how to get the x stuff on the left side?
Steve dnt be harsh it was jxt a ques . . (Eye wink) the easy way goes lyk dis first fynd lcm . Cros multiply then colect like term to d right side. Soln. -2x/5 -3=5y. .lcm is 15 it b coms. -2x -15 =5y den colet lyk term 2x +15=5y or 2x +5y =-15
I don't trust any answer from a person who appears to be illiterate.
To write the equation y = -2/5x - 3 in standard form using integers, we need to eliminate the fraction by multiplying all terms by the common denominator of 5.
First, let's rewrite the equation:
y = -2/5x - 3
Multiply all terms by 5 to get rid of the fraction:
5y = (-2/5)(5x) - (3)(5)
Simplify:
5y = -2x - 15
Now, we want all the terms on one side of the equation and the constant term on the other side. To achieve this, let's move the 5y term to the same side as the -2x term:
5y + 2x = -15
Now, the equation is in standard form with all coefficients as integers. Therefore, the answer is 5y + 2x = -15.