water has a chemical formula h2O which means each molecule of water contains two atoms of hydrogen one atom of oxygen if oxygen atom has a mass 16 times as much as the hydrogen one .what are the propotions of oxygen and hydrogen in 2kkg of water
regardless of the total mass, the proportion is clearly
16:2
To determine the proportions of oxygen and hydrogen in 2 kg of water, we need to consider the molar masses of each element.
The molar mass of hydrogen (H) is approximately 1 g/mol, while the molar mass of oxygen (O) is approximately 16 g/mol (as stated in the question).
Now, let's calculate the molar masses of the atoms in water:
- Two hydrogen atoms have a combined mass of 2 x 1 g/mol = 2 g/mol.
- One oxygen atom has a mass of 1 x 16 g/mol = 16 g/mol.
Therefore, in 1 mole of water (H2O), the mass of hydrogen is 2 g and the mass of oxygen is 16 g.
To determine the proportions in 2 kg (2000 g) of water, we can set up a ratio using the molar masses:
Proportion of hydrogen (H):
(2 g / (2 g + 16 g)) x 100% = (2 g / 18 g) x 100% = 11.11%
Proportion of oxygen (O):
(16 g / (2 g + 16 g)) x 100% = (16 g / 18 g) x 100% = 88.89%
Therefore, in 2 kg of water, the proportions of hydrogen and oxygen are approximately 11.11% and 88.89% respectively.
To find the proportions of oxygen and hydrogen in 2 kg of water, we need to first calculate the number of moles of water in 2 kg.
The molar mass of water (H2O) is calculated by adding the molar mass of hydrogen (H) and the molar mass of oxygen (O).
The molar mass of hydrogen (H) is approximately 1 g/mol, and the molar mass of oxygen (O) is 16 g/mol.
Therefore, the molar mass of water (H2O) is 2(1 g/mol) + 16 g/mol = 18 g/mol.
We can calculate the number of moles of water (n) in 2 kg using the following equation:
n = (mass of water) / (molar mass of water)
n = (2000 g) / (18 g/mol)
n ≈ 111.11 mol
According to the chemical formula of water (H2O), for every 1 mole of water, we have 2 moles of hydrogen (H) and 1 mole of oxygen (O).
Therefore, in 111.11 moles of water, there are:
- 2 * 111.11 = 222.22 moles of hydrogen (H)
- 1 * 111.11 = 111.11 moles of oxygen (O)
To find the mass of hydrogen and oxygen in 2 kg of water, we can multiply the number of moles by the molar mass of each element.
The mass of hydrogen (H) can be calculated as follows:
mass of hydrogen = (number of moles of hydrogen) * (molar mass of hydrogen)
mass of hydrogen = 222.22 mol * 1 g/mol
mass of hydrogen = 222.22 g
The mass of oxygen (O) can be calculated as follows:
mass of oxygen = (number of moles of oxygen) * (molar mass of oxygen)
mass of oxygen = 111.11 mol * 16 g/mol
mass of oxygen = 1777.76 g
Therefore, in 2 kg of water, the proportions of hydrogen and oxygen are approximately:
- Hydrogen (H): 222.22 g
- Oxygen (O): 1777.76 g