P is parallel to q
m angle 1 =(6x+y-4)
m angle 2 = (x+9y+1)
m angle 3 = (11x+2)
A. Set up an equation(s) to find x and y.
B. Show all work and solve for x and y.
C. Use these values to find the values of angles 1, 2, and 3.
Cant figure this out at all. keep geeting the wrong answer
Help me I don't get this math homework
Without either a diagram or a description, it's impossible to answer these questions.
The parallel lines indicate to me that there are probably some
alternate interior/exterior angles
adjacent angles
alternate angles are equal
adjacent angles add to 180
I expect you can use that info to set up some equations with x and y.
To solve this problem, we need to use the fact that lines that are parallel have the same slope. We can set up a system of equations based on the given information.
Let P and Q be two parallel lines. The given information tells us:
m angle 1 = 6x + y - 4
m angle 2 = x + 9y + 1
m angle 3 = 11x + 2
Since P and Q are parallel, their slopes must be equal.
The slopes can be determined from the coefficients of x and y in the equations for angle 1 and angle 2. In this case, the slopes are:
- For P: m angle 1 slope = 6
- For Q: m angle 2 slope = 1
This means that 6x + y - 4 is the equation for line P, and x + 9y + 1 is the equation for line Q.
Now we have two lines, P and Q, and we can set up a system of equations to find the values of x and y:
6x + y - 4 = x + 9y + 1 (equation for P)
Subtract x and 9y from both sides:
5x - 8y - 4 = 1
To eliminate the variable x, we can use the equation for line Q:
x + 9y + 1 = 0
Multiply the equation for line Q by 5 (the coefficient of x in equation for line P):
5x + 45y + 5 = 0
Now we have two equations:
5x - 8y - 4 = 1
5x + 45y + 5 = 0
We can solve this system of equations by using the method of elimination.
Multiply the first equation by 45, and the second equation by 8 to eliminate x:
225x - 360y - 180 = 45
40x + 360y + 40 = 0
Adding the two equations together eliminates the y variable:
265x - 140 = 0
Solve for x:
265x = 140
x = 140/265
x = 0.5283 (to several decimal places)
Now substitute the value of x back into one of the original equations to solve for y. Let's use the equation for line Q:
x + 9y + 1 = 0
0.5283 + 9y + 1 = 0
9y = -1.5283
y = -1.5283/9
y = -0.1698 (to several decimal places)
We have found the values of x and y, which are approximately x = 0.5283 and y = -0.1698.
To find the values of angles 1, 2, and 3, substitute these values back into their respective equations:
m angle 1 = 6x + y - 4
m angle 2 = x + 9y + 1
m angle 3 = 11x + 2
m angle 1 = 6(0.5283) + (-0.1698) - 4
m angle 2 = (0.5283) + 9(-0.1698) + 1
m angle 3 = 11(0.5283) + 2
Evaluating these expressions, we will get the values of angles 1, 2, and 3.