A simple machine with an efficiency of 75% lift of a load of 5000N.When a force of 500N is applied to it,Calculate the velocity ratio of the machine.
well, the real load is 500*4/3, so force ratio is 5000/500 * 3/4=7.5
velocity ratio then is 1/7.5
If I understand what you asked.
A simple machine has an efficiency of 0.75 and VR of 10 . determine the MA and the load that can be moved if an effort of 100N is applied
A simple machine has an efficiency of 0.75 and VR of 10.determine the MA and the load that can be moved if an effort of 100N is applied
To calculate the velocity ratio of the machine, we need to understand the definition of efficiency and how it relates to the machine's input and output.
Efficiency is defined as the ratio of output energy or work to the input energy or work, expressed as a percentage. In this case, the machine has an efficiency of 75%, which means it converts 75% of the input work into useful output work.
Given that the machine lifts a load of 5000N and a force of 500N is applied to it, we can calculate the work done by the input force as follows:
Input work = Input force × Input distance
The input distance is not provided in the given information. However, to calculate the velocity ratio, we do not require the actual values of forces or distances. Instead, we can use the principle that work done by the input force is equal to the work done by the output force.
Therefore, the output work done by the machine is:
Output work = Output force × Output distance
Since we know that the efficiency of the machine is 75%, we can express it as a decimal (75% = 0.75).
Efficiency = Output work / Input work
0.75 = Output work / Input work
Thus, the output work is 0.75 times the input work.
Substituting the equations for the work done by the input and output forces:
0.75 × Input work = Output force × Output distance
We know that the output force is 5000N, so we can rewrite the equation as:
0.75 × Input work = 5000N × Output distance
To calculate the velocity ratio, we need to find the ratio of the input distance to the output distance. Since the input distance is unknown, we'll call it "D1," and since the output distance is also unknown, we'll call it "D2."
If we divide the equation by the input force (500N), we get:
(0.75 × Input work) / 500N = (5000N × Output distance) / 500N
Simplifying the equation:
(0.75 × Input work) / 500N = 5000N / 500N × (Output distance / 500N)
0.75 × (Input work / 500N) = 10 × (Output distance / 500N)
Dividing both sides by 0.75:
(Input work / 500N) = 10 × (Output distance / 500N)
Since the units of N (Newton) cancel out, we can simplify further:
Input work = 10 × Output distance
Thus, the velocity ratio of the machine is 10:1.