5yrs ago,a mother was twice as old as her son.in 6yrs time,their ages sum 82,find their present ages
m-5 = 2(s-5)
m+6 + s+6 = 82
Now just solve for m and s.
I DON'T KNOW IT
To find their present ages, we'll use a system of equations.
Let's assume the current age of the son is x years.
The current age of the mother would then be (x + 5) years, as 5 years ago, the mother was twice as old as her son.
According to the given information, in 6 years, their ages will sum to 82. Hence, we can form the following equation:
(x + 6) + (x + 5 + 6) = 82
Simplifying the equation:
2x + 17 = 82
2x = 82 - 17
2x = 65
x = 65/2
x = 32.5
Since we cannot have fractional ages, we'll round down the value to the nearest whole number. Therefore, the son's current age is 32 years.
The mother's current age would be (32 + 5) = 37 years.
So, their present ages are the son is 32 years old, and the mother is 37 years old.