Assume that a device exists between two nodes A and B of a circuit and that the voltages of these two nodes A and B are equal to 2V and -3V respectively
What is the voltage drop across the device?
So I think I just go A-B , but it might also be B-A so either 5 or -5. im not sure..
Technically it could be either...
well it asks for the "drop", not just the difference so I guess I would say it dropped 5
However the question is poorly worded.
poorly worded is very kind.
Vb-a = 3 + 2 = 5 Volts.
Va-b = -2 + -3 = -5 Volts.
If the problem asked for Vb-a, I
would say, +5 volts. If it asked for Va-b, I would say negative 5
volts. But it didn't ask for neither of the above; therefore,
my answer would be "Five volts".
To determine the voltage drop across the device, you need to calculate the difference in voltage between the two nodes. The voltage drop is always calculated from the higher potential to the lower potential. In this case, node A has a voltage of 2V, while node B has a voltage of -3V.
The voltage drop from node A to node B can be found by subtracting the voltage of node B from the voltage of node A:
2V - (-3V) = 2V + 3V = 5V
Therefore, the voltage drop across the device is 5V.