A line that is parallel to the graph of y=1/2x+7

I think it is 1/2.
A line that is perpendicular to the graph of y=-2x-3
I think this one is 1/2 as well.
Find the x-intercept of the graph of each equation.
3x+2y=7
2x+3y=7
I got (0,7) for both of them.

the 1st two answers are EQUATIONS of lines

parallel lines have the same slope
so just change the +7 to something else

you are right about the perpendicular slope__so change the -2 to 1/2

the x-intercept means that y equals zero__so plug in zero for y and find x
the form will be (x,0)

To determine a line that is parallel or perpendicular to another line, we need to determine the slope of the given line. The equation of a line in slope-intercept form is y = mx + b, where m represents the slope of the line.

In the equation y = (1/2)x + 7, the slope of the line is 1/2. Parallel lines have the same slope, so a line parallel to this equation will also have a slope of 1/2.

For the equation y = -2x - 3, the slope is -2. Perpendicular lines have slopes that are negative reciprocals of each other. So, to find a line perpendicular to this equation, we need to flip the slope and change the sign. In this case, the perpendicular line will have a slope of 1/2.

To find the x-intercept of an equation, we set y = 0 and solve for x. The x-coordinate of the x-intercept represents the point where the line crosses the x-axis.

Let's find the x-intercept for the equation 3x + 2y = 7:
Setting y = 0, we get:
3x + 2(0) = 7
3x = 7
Dividing both sides by 3, we find:
x = 7/3
So the x-intercept for this equation is (7/3, 0).

Now, let's find the x-intercept for the equation 2x + 3y = 7:
Setting y = 0, we have:
2x + 3(0) = 7
2x = 7
Dividing both sides by 2, we get:
x = 7/2
So the x-intercept for this equation is (7/2, 0).

Therefore, the x-intercepts of the two equations are (7/3, 0) and (7/2, 0) respectively.