Force f1 of 3,5N acts on an object to the right and force f2 of 4,3N acts on the object towards the left. QUESTION is : Determine the resultant of the forces using an accurate tail to head vector diagram.Use a scale of 10mm : 1N
If we can do like this can be easily to others. Fr=F1+F2 and Fr=3,5N+(-4,3N) so the answer will be -0,8N to the left because the answer it have a negative sign which means is decreasing or loses energy
<---------.------------->
F1=3,5N
F2=-4,3N
10mm:1N
3,5 - 4,3 = -0,8
so the resultant points to the left.
I expect you can draw your own diagrams. Oh, wait -- maybe not, or you'd have seen the answer already...
To determine the resultant of the forces using a vector diagram, you can follow these steps:
1. Draw a straight line to represent the direction and orientation of the object's movement. This line is called the reference line or the base line.
2. Starting from the tail of the reference line, draw a vector to represent the force f1. The length of this vector will be determined by the scale of 10mm:1N. Since f1 is 3.5N, the length of the vector representing f1 will be 3.5 * 10 = 35mm.
3. From the head of the vector representing f1, draw another vector representing the force f2. Since f2 is 4.3N, the length of the vector representing f2 will be 4.3 * 10 = 43mm.
4. The resultant of the forces can now be determined by drawing a vector from the tail of the reference line to the head of the vector representing the sum of f1 and f2. This resultant vector represents the net force acting on the object.
5. Measure the length of the resultant vector using a ruler. Let's assume it measures 55mm.
6. Convert the measured length of the resultant vector back to the actual force using the same scale of 10mm:1N. In this case, 55mm represents 5.5N.
Therefore, the resultant of the forces is 5.5N, in the direction shown by the vector from the tail of the reference line to the head of the resultant vector.